How to find the value of x where $0<=x<=360^@$ for $csc x= -1.3737$ ?

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Answer 1 · 2015-06-01T02:18:33

$csc x = 1/sin x = -1.3737$ -> $sin x = 1/-1.3737 = -0.728$

On the trig unit circle:

-0.728 -> x = -46.71 or x = 360 - 46.71 = 313.29 deg

x = 180 + 46.71 = 226.71.

Within period $(0, 2pi)$ , there are 2 answers:

x = 226.71 and x = 313. 29 deg

How to find the value of x where 0<=x<=360^@0<=x<=360^@ for csc x= -1.3737csc x= -1.3737?