How to find the value of x where $0 \leq x \leq 360^{\circ}$ $0<=x<=360^@$ for $sec x = 3.1909$ $sec x= 3.1909$ ?

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Answer 1 · 2015-05-31T02:43:34

$sec x = \frac{1}{cos x} = 3.1909 \to cos x = \frac{1}{3.1909} = 0.31$ $sec x = 1/cos x = 3.1909 -> cos x = 1/3.1909 = 0.31$

$cos x = 0.31 \to x = \pm 71.94 d e g$ $cos x = 0.31 -> x = +- 71.94 deg$

Within period (0, 2pi):

x = 71.94 deg
x = 360 - 71.94 = 288.06 deg

How to find the value of x where 0≤x≤360∘0<=x<=360^@ for secx=3.1909sec x= 3.1909?