How to graph a parabola $y = (\frac{1}{8}) x^{2}$ $y=(1/8)x^2$ ?

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Answer 1 · 2015-05-15T07:45:15

Graph the parabola $y = \frac{1}{8} x^{2}$ $y=1/8x^2$ .

Determine points on the parabola. You must include positive and negative values for $x$ $x$ .

If $x=-4; y=(1/8)(-4)^2=1/cancel8^1*cancel16^2=2$ ; Point $(-4, 2)$

If $x=-2; y=(1/8)(-2)^2=1/cancel8^2*cancel4^1=1/2$ ; Point $(-2, 1/2)$

If $x=0; y=1/8$ ; Point $(0,1/8)$

If $x=2; y=1/8(2)^2=1/cancel8^2*cancel4^1=1/2$ ; Point $(2,1/2)$

If $x=-4; y=1/8(-4)^2=1/cancel8^1*cancel16^2=2$ ; Point $(-4,2)$

Plot the points and connect the points.

graph{y=1/8x^2 [-6.25, 6.244, -3.13, 3.12]}

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