Question

How to graph a parabola `y>x^2+2x-3`?

Answer 1

The function can be rewritten as `y>(x-1)(x+3)`

This gives you the Zeroes `x=1andx=-3`
The minimum will be reached halfway between those (when `x=-1`) at the point `(-1,-4)`
Everything above the graph is your solution space.
graph{x^2+2x-3 [-10, 10, -5, 5]}