How would you determine the molecular formula of C4H9?

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How would you determine the molecular formula of C4H9?

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Answer 1 · 2018-08-06T08:39:30

Just to retire this question ... are you sure that it is correctly posed...?

Explanation:

$C_{4} H_{9}$ $C_4H_9$ is not the formula of anything you could put in a bottle. It is the radical of some butane derivative, i.e. $C_{4} H_{10}$ $C_4H_10$ ..

And so we have (possibly) $tert-butyl radical$ $"tert-butyl radical"$ ... ${(H_{3} C)}_{3} C \cdot$ $(H_3C)_3C*$ , the which is relatively long-lived...

On the other hand, you MIGHT have quoted an empirical formula of $C_{4} H_{9}$ $C_4H_9$ ...to get the molecular formula, we need a measurement of the molecular mass...say we got a mass of $114.22 \cdot g \cdot m o l^{- 1}$ $114.22*g*mol^-1$ ...this would correspond to a molecular formula of $C_{8} H_{18}$ $C_8H_18$ ...and this is a saturated formula...

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How would you determine the molecular formula of C4H9?

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