How would you find the period of this equation $y= -5sin2(x - π/6) + 1$ ?

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Answer 1 · 2015-11-09T16:14:28

Find the period by dividing $2pi$ by the coefficient on the variable x

For this function, the coefficient on x is 2.

Period $=(2pi)/2=pi$

hope that helped

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How would you find the period of this equation y= -5sin2(x - π/6) + 1y= -5sin2(x - π/6) + 1?