If 2#cos^2x# - #cosx# = 1 , what is the value of #x#? Precalculus Graphs of Trigonometric Functions Graphing Sine and Cosine 1 Answer Azhar A. Apr 2, 2016 #x=0# Explanation: As we know: #cos 0 =1# Put #x=0# in equation: #2cos^(2)0-cos0=1# #2*1-1=1# #1=1# #L.H.S=R.H.S# Answer link Related questions What is the y-intercept of the graph of #y = sin x#? What is the graph of #y=sin (x/3)#? What is the graph of #y=sin(x+30)#? What is the graph of #y=sin(x-pi/4)#? What is the graph of #y=sin(x/2)#? What is the amplitude of the graph of #y = sin x#? What is the range of the graph of #y = sin x#? What are the x-intercepts of the graph of #y = cos x#? What is the domain of the graph of #y = cos x#? What is the maximum value that the graph of #y=cos x# assumes? See all questions in Graphing Sine and Cosine Impact of this question 1990 views around the world You can reuse this answer Creative Commons License