Let m be Mac's Mass
and convert the description a bit at a time into algebraic form:
5kg more than 3 times color(green)("Mac's Mass") is decreased by twice color(green)("his mass"), the result is 60kg
rArr5kg more than 3 times color(green)(m) is decreased by twice color(green)(m), the result is 60kg
5kg more than color(red)(3" times "m) is decreased by color(blue)(" twice "m), the result is 60kg
rArr5kg more than color(red)(3m) is decreased by color(blue)(2m), the result is 60kg
color(green)(5"kg more than "3m) is decreased by 2m, the result is 60kg
rArrcolor(green)(5+3m) is decreased by 2m, the result is 60kg
color(red)((5+3m)" is decreased by "2m), the result is 60kg
rArr
color(red)((5+3m)-2m), the result is 60kg
((5+3m)-2m)color(blue)(" the result is "60"kg")
rArr((5+3m)-2m)color(blue)(=60"kg")
So we have:
(5+3m)-2m = 60
Combining the m terms on the left side:
5+m = 60
Subtracting 5 from both sides:
m = 55