Question

If 60 liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, what will the new volume of the gas be?

Answer 1

Data:-
Initial Volume`=V_1=60 liter`
Initial Temperature`=T_1=546K`
Final Temperature`=T_2=273K`
Final Vloume`=V_2=??`
Sol:-

Since the pressure is constant and the question is asking about temperature and volume, i.e,
`V_1/T_1=V_2/T_2`

`implies V_2=(V_1*T_2)/T_1=(60*273)/546=60/2=30liter`

`implies V_2=30 liter`

Hence the new volume of the gas is `30 liter`