Question

If `a=(b^2-c)/2`, how do you find the value of a when b=2, c=-4?

Answer 1

`a=4`

Explanation:

WE have `b=2` hence `b^2=2xx2=4` and have `c=-4`

Hence `a=(b^2-c)/2=(4-(-4))/2=(4+4)/2=8/2=4`