If $a_n=1/3*6^(n-1)$ , what is $a_6$ ?

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Answer 1 · 2016-10-20T09:47:13

$a_6=2592$

If $a_n=1/3*6^(n-1)$ ,

we can find $a_6$ by substituting $n$ by $6$ .

Hence $a_6=1/3*6^(6-1)$

= $1/3*6^5$

= $(6xx6xx6xx6xx6)/3$

= $(2cancel6xx6xx6xx6xx6)/(1cancel3)$

= $2592$

If a_n=1/3*6^(n-1)a_n=1/3*6^(n-1), what is a_6a_6?