If a projectile is shot at an angle of 5π12 and at a velocity of 19ms, when will it reach its maximum height??

1 Answer
Apr 1, 2017

The projectile will reach its maximum height when the velocity equals zero.

Explanation:

At an angle of (5π12), the initial velocity forms the hypotenuse of a right-angled triangle with angle (5π12) at the base.
The maximum height of the shot will be the vertical component (y), of the initial velocity vector of 19 m/s, and will occur when the final velocity equals zero.
The initial velocity of the vertical component is Voy=19sin(5π12)=0.434 m/s.
Using V=Vo+at we can rearrange to find t:

t=VVoa

=00.4349.8=0.04s

Assuming that the force due to gravity is in the downward direction, therefore, the upward direction has a negative sign.