Question

If a projectile is shot at an angle of `(7pi)/12` and at a velocity of `21 m/s`, when will it reach its maximum height??

Answer 1

At the maxima of a projectile's parabolic trajectory, `nu_y = 0`.

Given,

`nu_(y0) = nusin(theta) = (20.2"m")/"s"`
`nu_"y" = 0`
`a_y = g`

Recall,

`nu = nu_0 + at`

Hence, it will take,

`=> t = (Deltanu)/a approx 2.07"s"`

for the projectile to reach its maximum height.