If a projectile is shot at an angle of #pi/4# and at a velocity of #12 m/s#, when will it reach its maximum height??

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Answer 1 · 2017-01-15T11:10:37

The maximum height is #=3.67m#

The vertical motion is #uarr^+#

#u=12sin(pi/4)ms^-1#

#v=0ms^-1#

#a=-g=-9.8ms^-2#

We use the equation

#v^2=u^2+2as#

#0=144sin^2(pi/4)-2*9.8*h#

#h=(144*sin^2(pi/4))/(2*9.8)=3.67m#