If a projectile is shot at an angle of #(pi)/8# and at a velocity of #7 m/s#, when will it reach its maximum height?

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Answer 1 · 2017-04-17T11:15:42

The time is #=0.27s#

Resolving in the vertical direction #uarr^+#

initial velocity is #u_y=vsintheta=7*sin(1/8pi)#

At the maximum height, #v=0#

We apply the equation of motion

#v=u+at#

to calculate the time to reach the greatest height

#0=7sin(1/8pi)-g*t#

#t=7/g*sin(1/8pi)#

#=0.27s#