Question

If `f(x)=4x^3-4x^2+10` then how do you find `f(-2)`?

Answer 1

Just put `-2` in place of the `x`'s

`f(x)=4*x^3-4*x^2+10`

So:
`f(-2)=4*(-2)^3-4*(-2)^2+10`
`=4*(-8)-4*(4)+10`
`=-32-16+10`
`=-38`

Answer :

`f(-2)=-38`