If $f (x) = 4 x^{3} - 4 x^{2} + 10$ $f(x)=4x^3-4x^2+10$ then how do you find $f (- 2)$ $f(-2)$ ?

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If $f (x) = 4 x^{3} - 4 x^{2} + 10$ $f(x)=4x^3-4x^2+10$ then how do you find $f (- 2)$ $f(-2)$ ?

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Answer 1 · 2015-02-06T00:02:27

Just put $- 2$ $-2$ in place of the $x$ $x$ 's

$f (x) = 4 \cdot x^{3} - 4 \cdot x^{2} + 10$ $f(x)=4*x^3-4*x^2+10$

So:
$f (- 2) = 4 \cdot {(- 2)}^{3} - 4 \cdot {(- 2)}^{2} + 10$ $f(-2)=4*(-2)^3-4*(-2)^2+10$
$= 4 \cdot (- 8) - 4 \cdot (4) + 10$ $=4*(-8)-4*(4)+10$
$= - 32 - 16 + 10$ $=-32-16+10$
$= - 38$ $=-38$

Answer :

$f (- 2) = - 38$ $f(-2)=-38$

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If $f (x) = 4 x^{3} - 4 x^{2} + 10$ $f(x)=4x^3-4x^2+10$ then how do you find $f (- 2)$ $f(-2)$ ?

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If f(x)=4x3−4x2+10f(x)=4x^3-4x^2+10 then how do you find f(−2)f(-2)?

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If $f (x) = 4 x^{3} - 4 x^{2} + 10$ $f(x)=4x^3-4x^2+10$ then how do you find $f (- 2)$ $f(-2)$ ?