If F(x) = sqrt 64 - x^2, what is f(x)?

1 Answer
Jan 27, 2015

It your function is as shown, it would be f(x)=-2x

Because root 2 64 = 8->F(x)=8-x^2

But I think you meant root 2 (64-x^2)= root 2 ((8+x)(8-x)

Please confirm in a comment, before I go any further.

BTW :
We use the f(x)->f'(x) notation.
I hardly ever see the F(x)->f(x)