If #x^2=4(5-1)# what is the value of x? Algebra Quadratic Equations and Functions Use Square Roots to Solve Quadratic Equations 1 Answer Daniel L. Nov 28, 2016 This equation has 2 solutions: #x=-4 vv x=4# Explanation: #x^2=4(5-1)# First we have to multiply the right side. #x^2=4*4# #x^2=16# Now we can take a square root of both sides remembering that #sqrt(x^2)=|x|# #|x|=4# #x=-4 vv x=4# Answer link Related questions Can you use square roots to solve all quadratic equations? How do you use square roots to solve quadratic equations? How do you solve #4x^2-49=0# by taking square roots? How do you solve #(x-3)^2+25=0#? How do you use square roots to solve #2(x+3)^2=8#? What is Newton's formula for projectile motion? How do you solve for x in the equation #(x-3)^2+25=0#? How do you solve the equation #3(x-2)^2-12=0# How do you solve #3x^2+8x=9+2x#? How do you solve #4x^2=52# solve using the square root property? See all questions in Use Square Roots to Solve Quadratic Equations Impact of this question 4060 views around the world You can reuse this answer Creative Commons License