If x=6 and y=-2, what is the value of 3xy+2x^2-y^33xy+2x2y3?

1 Answer
Jan 10, 2017

4444

Explanation:

Substituting color(red)(6)6 for xx and color(blue)(-2)2 for yy gives:

3color(red)(x)color(blue)(y) + 2color(red)(x)^2 - color(blue)(y)^3 ->3xy+2x2y3

(3 xx color(red)(6) xx color(blue)(-2)) + (2 xx color(red)((6)^2)) - (color(blue)(-2))^3 ->(3×6×2)+(2×(6)2)(2)3

(-36) + (2 xx 36) - (-8) ->(36)+(2×36)(8)

-36 + 72 + 8 ->36+72+8

4444