If x=6 and y=-2, what is the value of $3xy+2x^2-y^3$ ?

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Answer 1 · 2017-01-10T17:33:11

$44$

Substituting $color(red)(6)$ for $x$ and $color(blue)(-2)$ for $y$ gives:

$3color(red)(x)color(blue)(y) + 2color(red)(x)^2 - color(blue)(y)^3 ->$

$(3 xx color(red)(6) xx color(blue)(-2)) + (2 xx color(red)((6)^2)) - (color(blue)(-2))^3 ->$

$(-36) + (2 xx 36) - (-8) ->$

$-36 + 72 + 8 ->$

$44$

If x=6 and y=-2, what is the value of 3xy+2x^2-y^33xy+2x^2-y^3?