Question

If you have 0.250 mol of Al, a) what is the mass of the sample, and b) how many atoms are in the sample?

Answer 1

`6.75g` and `1.51*10^23` `Al` atoms.

Explanation:

a.) What's the mass?

Use the element/compound's molar mass.

`0.250mol*(27.0g)/(mol) = 6.75g` of `Al`

b.) How many atoms are in the sample?

Use Avogadaro's number.

`0.250mol * (6.023*10^23 " Al atoms")/(mol) = 1.51*10^23` `Al` atoms