Is (0,1) a solution to $1 - x \geq 3 y, 3 y - 1 > 2 x$ $1-x>=3y, 3y-1>2x$ ?

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Answer 1 · 2017-07-20T18:13:39

See a solution process below:

Substituting $0$ $0$ for $x$ $x$ and $1$ $1$ for $y$ $y$ in the first inequality gives:

$1 - 0 \geq 3 \cdot 1$ $1 - 0 >= 3 * 1$

$1 \geq 3$ $1 >= 3$

This is not true therefore $(0, 1)$ $(0, 1)$ is not a solution.

Is (0,1) a solution to 1-x>=3y, 3y-1>2x1−x≥3y,3y−1>2x1-x>=3y, 3y-1>2x?