Is f(x)=1-xe^(-3x) concave or convex at x=-2? Calculus Graphing with the Second Derivative Analyzing Concavity of a Function 1 Answer Harish Chandra Rajpoot Jul 27, 2018 function is convex at x=-2 Explanation: Given function: f(x)=1-xe^{-3x} f'(x)=-x(-3e^{-3x})-e^{-3x}(1) f'(x)=e^{-3x}(3x-1) f''(x)=e^{-3x}(3)+(3x-1)(-3e^{-3x}) f''(x)=e^{-3x}(6-9x) f''(-2)=e^{6}(6-9(-2)) =24e^{6} Since f(-2)>0 hence the given function is convex at x=-2 Answer link Related questions How do you determine the concavity of a quadratic function? How do you find the concavity of a rational function? What is the concavity of a linear function? What x values is the function concave down if f(x) = 15x^(2/3) + 5x? How do you know concavity inflection points, and local min/max for f(x) = 2x^3 + 3x^2 - 432x? How do you determine the concavity for f(x) = x^4 − 32x^2 + 6? How do you find the intervals on which the graph of f(x)=5sqrtx-1 is concave up or is concave... How do you determine where the given function f(x) = (x+3)^(2/3) - 6 is concave up and where... How do you determine the intervals on which function is concave up/down & find points of... On what intervals the following equation is concave up, concave down and where it's inflection... See all questions in Analyzing Concavity of a Function Impact of this question 1808 views around the world You can reuse this answer Creative Commons License