Is it possible to factor $y=2x^2+4x+8$ ? If so, what are the factors?

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Answer 1 · 2015-12-05T06:57:59

Yes it is possible to factorise $2x^2+4x+8$
The factors are 2, $(x+1-i sqrt(3))$ , $(x+1+i sqrt(3))$

$2x^2+4x+8$ =2( $x^2+2x+4$ )

$x^2+2x+4$ = $(x+1-i sqrt(3))$ $(x+1+i sqrt(3))$

Is it possible to factor y=2x^2+4x+8 y=2x^2+4x+8 ? If so, what are the factors?