Is it possible to factor $y = 3 x^{2} + 10 x - 8$ $y=3x^2 +10x - 8$ ? If so, what are the factors?

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Is it possible to factor $y = 3 x^{2} + 10 x - 8$ $y=3x^2 +10x - 8$ ? If so, what are the factors?

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Answer 1 · 2016-05-10T14:48:26

Yes. $y = (3 x - 2) (x + 4)$ $y=(3x-2)(x+4)$

Explanation:

In order to factor this expression you need to find factors of 3 and 8 that add or subtract to give 10. Because the middle term is positive and the last term is negative the result must be arrived at by subtraction.

The factors of $3$ $3$ can only be $3$ $3$ and $1$ $1$ . The factors of $8$ $8$ can be $8$ $8$ and $1$ $1$ or $4$ $4$ and $2$ $2$ .
By trial and error you can get $3 \cdot 4 = 12$ $3*4 = 12$ and $1 \cdot 2 = 2$ $1*2 = 2$ . $12 - 2 = 10$ $12-2 = 10$

$:. y=(3x-2)(x+4)$

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Is it possible to factor $y = 3 x^{2} + 10 x - 8$ $y=3x^2 +10x - 8$ ? If so, what are the factors?

1 Answer

Explanation:

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Science

Math

Humanities

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Is it possible to factor y=3x^2 +10x - 8 y=3x2+10x−8y=3x^2 +10x - 8 ? If so, what are the factors?

1 Answer

Explanation:

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Is it possible to factor $y = 3 x^{2} + 10 x - 8$ $y=3x^2 +10x - 8$ ? If so, what are the factors?