Is it possible to factor $y=4x^2-49$ ? If so, what are the factors?

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Answer 1 · 2015-12-10T04:08:44

$color(blue)((2x-7) , (2x+7)$ are the factos of the expression.

$y=4x^2-49$

The expression can be re written as:
$y=(2x)^2-7^2$ , this is of the below format:

$color(blue)(a^2-b^2=(a-b)(a+b)$

So,
$y=(2x)^2-7^2 = color(blue)((2x-7)(2x+7)$

$color(blue)((2x-7)(2x+7)$ is the factorised form of the expression.

Is it possible to factor y=4x^2-49 y=4x^2-49 ? If so, what are the factors?