Is it possible to factor $y=4x^2 - 8x + 3$ ? If so, what are the factors?

Question

2889 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-06T11:24:15

$x= 3/2 or 1/2$

The coefficient of $x^2$ is positive so the graph is of format type $uu$ so the vertex is a minimum.

Standard equation for: $y=ax^2+bx+c$

Where $a=4"; "b=-8"; "c=+3$

and $" " x=(-b+-sqrt(b^2-4ac))/(2a)$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$x= (+8+-sqrt((-8)^2-4(4)(3)))/( 2(4))$

$x= 1+-sqrt(16 )/8$

$x= 3/2 or 1/2$

Is it possible to factor y=4x^2 - 8x + 3 y=4x^2 - 8x + 3 ? If so, what are the factors?