Is it possible to factor y=x^2/2+4x+8 ? If so, what are the factors?

1 Answer
Jim G.
May 31, 2018

y=1/2(x+4)^2

Explanation:

"take out a "color(blue)"common factor "1/2

y=1/2(x^2+8x+16)

x^2+8x+16" is a "color(blue)"perfect square"

=(x+4)(x+4)=(x+4)^2

y=1/2x^2+4x+8=1/2(x+4)^2

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