Is #-sqrt54# a rational or irrational number? Algebra Properties of Real Numbers Order of Real Numbers 1 Answer MeneerNask Jul 13, 2015 It's irrational. Explanation: #sqrt54=sqrt(6*9)=3sqrt6# #sqrt6# cannot be resolved further, so there is no ratio to express #sqrt6#. Answer link Related questions What are Real Numbers? What does it mean to order a set of real numbers? What are the different types of rational numbers? What kind of rational number is 0? How do you classify real numbers? How do you compare real numbers? What are examples of non real numbers? How would you categorize the number #\frac{\sqrt{36}}{9}#? Which number is larger between #\frac{\pi}{15}# and #\frac{\sqrt{3}}{\sqrt{75}}#? How would you classify each of the following numbers: #\frac{\sqrt{12}}{2}, 1.5\cdot \sqrt{3},... See all questions in Order of Real Numbers Impact of this question 3687 views around the world You can reuse this answer Creative Commons License