Is the following trinomial $x^{2} + 18 x + 81$ $x^2 + 18x + 81$ a perfect square?

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Is the following trinomial $x^{2} + 18 x + 81$ $x^2 + 18x + 81$ a perfect square?

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Answer 1 · 2015-04-08T11:47:44

Since $x^{2} + 18 x + 81 = {(x + 9)}^{2}$ $x^2+18x+81 = (x+9)^2$

$x^{2} + 18 x + 81$ $x^2+18x+81$ is considered a perfect (polynomial) square
even though (if $x$ $x$ is not an integer) its value might not be a perfect square.

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Is the following trinomial $x^{2} + 18 x + 81$ $x^2 + 18x + 81$ a perfect square?

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