Question

Is the x-intercept of the graph of `y=ax^2` always 0?

Answer 1

Yes

Explanation:

In order to find the `x`-intercept of a function, `f`, we have to set `y` equal to `0`. (This is because the `x`-intercept has a `y`-value of `0`.)

`y=ax^2=0`

`a=0 larr` This can't be the case because we would have no function.

`x^2=0`

`x=sqrt0=0`

Thus, we have proven that, for any value of `a` of the function `f`, `ax^2 -=0`