Lnx-ln5=10?

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Answer 1 · 2018-02-13T14:46:44

#x =50#

We have:

# ln x -ln 5 = ln 10 #

Using the result lnA=lnB=ln(A/B)# we can write:

# ln(x/5) = ln10 #

The logarithm is a #1:1# function so:

# ln A= ln B iff A=B #

And so we have:

# x/5 = 10 => x =50#