Make $x$ the subject of $y= ( x - 4) ^ { 2} + 6$ ?

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Answer 1 · 2016-12-03T13:38:47

$x = +-sqrt(y-6) +4$

$y=(x-4)^2 +6$

$(x-4)^2=y-6$

Take the square root of both sides:

$sqrt((x-4)^2) = sqrt(y-6)$

$x-4= +- sqrt(y-6)$

Add $4$ on both sides of the equation

$x= +-sqrt(y-6) +4$

Make xx the subject of y= ( x - 4) ^ { 2} + 6y= ( x - 4) ^ { 2} + 6?