Microwave ovens emit microwave energy with a wavelength of 12.2 cm. What is the energy of exactly one photon of this microwave radiation?

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Microwave ovens emit microwave energy with a wavelength of 12.2 cm. What is the energy of exactly one photon of this microwave radiation?

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Answer 1 · 2016-05-07T10:37:15

$1.629 \times 10^{- 24} J$ $1.629xx10^-24J$ , rounded to three decimal places.

Explanation:

Let us calculate the frequency $ν$ $nu$ of the photon.
We have the expression between the velocity of light in vacuum $c = ν \times λ$ $c=nuxxlambda$
or $ν = \frac{c}{λ}$ $nu=c/lambda$ ......(1)

where $λ$ $lambda$ is the wave-length of the electromagnetic radiation. $c = 3 \times 10^{8} m s^{- 1}$ $c=3xx10^8ms^-1$

We also have the expression connecting frequency to energy of photon

$E = h ν$ $E=hnu$ .......(2)

where $h$ $h$ is Planck's Constant and is $6.626 \times 10^{- 34} m^{2} k g s^{- 1}$ $6.626xx 10^-34 m^2 kg s^-1$
From (1) and (2)
$E = h \times \frac{c}{λ}$ $E=hxxc/lambda$
Inserting the constant and given value, after converting wavelength into $m$ $m$
$E = 6.626 \times 10^{- 34} \times \frac{3 \times 10^{8}}{0.122}$ $E=6.626xx 10^-34xx(3xx10^8)/0.122$
or $E = 1.629 \times 10^{- 24} J$ $E=1.629xx10^-24J$ , rounded to three decimal places.

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Microwave ovens emit microwave energy with a wavelength of 12.2 cm. What is the energy of exactly one photon of this microwave radiation?

1 Answer

Explanation:

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