The number of moles present in $44 g$ $"44 g"$ of ${CO}_{2}$ $"CO"_2$ ?

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Answer 1 · 2018-02-17T15:36:53

$0.9998 mols \to 1.0 mols$ $"0.9998 mols" -> "1.0 mols"$ (2 sig figs)

$C O_{2}$ $CO_2$ has a molar mass of $44.009 \ "g/mol"$ . That means that one mole of $CO_2$ has a mass of $44.009 \ "g"$ .

So, in $44 \ "g"$ of $CO_2$ , there is a little under one mole of $"CO"_2$ .

The number of moles present in "44 g"44 g"44 g" of "CO"_2CO2"CO"_2 ?