Question

Ok can someone help me with a GAMSAT question on mechanical and gravitational energy?

Answer 1

`7`. C
`8`. C

Explanation:

(7). As the ball slides down the curved surface and there are no frictional forces the total mechanical energy at any instant of time remains constant due to the Law of Conservation of Energy.

(8) Decrease in gravitational potential energy

`DeltaGPE=mgDeltah`
where `deltah` is the change in height of center of mass of the ball. In SI units
`:.DeltaGPE=(50/1000)xx10xx7/100`
(`because` radius of curved surface `=8\ cm`. The center of ball is `1\ cm` above the point `T`)

`=>DeltaGPE=3.5xx10^-2\ J`