One solution of $k x^{2} - 5 x + k = 0$ $kx^2- 5x +k=0$ is 3. How do you find the other solution?

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Answer 1 · 2016-11-24T03:47:06

Other solution is $x = \frac{1}{3}$ $x=1/3$

As one solution of $k x^{2} - 5 x + k = 0$ $kx^2-5x+k=0$ is $3$ $3$ , we have

$k \times 3^{2} - 5 \times 3 + k = 0$ $kxx3^2-5xx3+k=0$

or $9 k - 15 + k = 0$ $9k-15+k=0$

or $10 k = 15$ $10k=15$ i.e. $k = 1.5$ $k=1.5$

Hence equation is $1.5 x^{2} - 5 x + 1.5 = 0$ $1.5x^2-5x+1.5=0$

or $3 x^{2} - 10 x + 3 = 0$ $3x^2-10x+3=0$

or $3 x^{2} - 9 x - x + 3 = 0$ $3x^2-9x-x+3=0$

or $(3 x (x - 3) - 1 (x - 3) = 0$ $(3x(x-3)-1(x-3)=0$

or $(3 x - 1) (x - 3) = 0$ $(3x-1)(x-3)=0$

$:.$ either $3x-1=0$ i.e. $x=1/3$

or $x-3=0$ i.e. $x=3$

Hence, other solution is $x=1/3$

One solution of kx^2- 5x +k=0kx2−5x+k=0kx^2- 5x +k=0 is 3. How do you find the other solution?