Please help me with this logarithmic equation. How do I solve it?

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1 Answer
Dec 25, 2016

No real solution.

Explanation:

The feasible solutions are #(x > 0) nn (x(x^2-8x+25) > 0)# but for #x > 0# we have #x^2-8x+25 > 0# with minimum at #x =4# with value #4^2-8 cdot 4 + 25 = 9#

Now #log(x^3-8x^2+25x)-log(x)=log(x^2-8x+25)=1# or

#x^2-8x+25 = e# but as we saw previously #x^2-8x+25 ge 9# so no real solutions for this equation.