Rene is 6 years older than her younger sister. After 10 years, the sum of their ages will be 50 years. How do you find their present ages?

Question

28558 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-16T00:32:45

18, 12

Let's have R be Rene's age.

#R#

And we have a younger sister who is 6 years younger than Rene:

#R-6#

In 10 years, the sum of their ages will be 50. So in 10 years Rene will be:

#R+10#

and her sister will be

#R-6+10#

and the two added together will be 50:

#(R+10)+(R-6+10)=50#

How old are they now?

#(R+10)+(R-6+10)=50#

#2R+14=50#

#2R=36#

#R=18#

and her sister is

#R-6=18-6=12#