Probability with samples?

Answer whichever part (a-e) you can/want to :)


computercomputer

1 Answer
Jul 25, 2017

a) P(x\lt40)\approx0.189

b) P(\bar{x}\lt40),n=9\rArr\approx0.0041

c) P(\bar{x}\lt40),n=12\rArr\approx0.0011

d) not sure see explanation for more

e) unusual as it exceeds 2 z-scores (or 2 standard deviations)

Explanation:

Given information
\mu=43.7 cm, \sigma=4.2 cm

Working it out

a) P(X\lt40)=P(z\lt(40-43.7)/4.2)=P(z\lt-3.7/4.2)=P(z\lt-0.8810)\approx0.189


b) n=9\rarr\sigma_{\bar{x}}=4.2/\sqrt{9}=4.2\div3=1.4\rArrP(\bar{x}\lt40)=P(z\lt-3.7\div1.4)=P(z\lt-2.6429)\approx0.0041


c) n=12\rarr\sigma_{\bar{x}}=4.2/\sqrt{12}\approx1.2124\rArrP(\bar{x}\lt40)=P(z\lt-3.7\div1.2124)=P(z\lt-3.0517)\approx0.0011


d) Increasing sample size appears to lower probability. This is likely because --


e) n=15\rarr\sigma_{\bar{x}}=4.2/\sqrt{15}\approx1.0844\bar{x}=46;z=(46-43.7)/(1.0844)\approx2.1209
This result is unusual as it exceeds a z-score of 2.