Simplify: (12−5^2-:5)*4^2-:2^3+2^2−1+[(2^4-:2^3)^3+4^3-:4+2^5]-:7? Prealgebra Fractions Equivalent Fractions and Simplifying 1 Answer Shwetank Mauria May 2, 2016 (12-5^2-:5)*4^2-:2^3+2^2-1+[(2^4-:2^3)^3+4^3-:4+2^5]-:7=25 Explanation: (12-5^2-:5)*4^2-:2^3+2^2-1+[(2^4-:2^3)^3+4^3-:4+2^5]-:7 = (12-25-:5)*4^2-:2^3+2^2-1+[(2)^3+4^2+2^5]-:7 = (12-5)*(2^2)^2-:2^3+2^2-1+[8+16+32]-:7 = 7*2^4-:2^3+2^2-1+56-:7 = 7*2+4-1+8 = 14+4-1+8 = 25 Answer link Related questions What is 0.098 divided by 7? How do you find the fraction notation and simplify 16.6%? How do you convert 0.bar(45) (meaning the 45 is being repeated) to a fraction? How do you convert 0.40 (40 repeating) to a fraction? How do you convert 8/15 to a decimal? How do you express 3/4, 7/16, and 5/8 with the LCD? How do you simplify fractions? What is the simplified form of 30/42? How do you subtract and simplify 9-5 1/3? How do you add and simplify 5/7 + 3/4? See all questions in Equivalent Fractions and Simplifying Impact of this question 4029 views around the world You can reuse this answer Creative Commons License