Simplify $\sqrt{- 64}$ $sqrt(-64)$ ? Thanks

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Simplify $\sqrt{- 64}$ $sqrt(-64)$ ? Thanks

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Answer 1 · 2018-03-01T21:24:45

$8 i$ $8i$

Explanation:

$\sqrt{- 64} = \sqrt{- 1 \cdot 64}$ $sqrt(-64) = sqrt(-1 * 64)$

$= \sqrt{- 1} \cdot \sqrt{64}$ $= sqrt(-1)*sqrt(64)$

$= \sqrt{- 1} \cdot 8 \to$ $= sqrt(-1)*8 " " ->$ since $i = \sqrt{- 1}$ $i=sqrt(-1)$

$= 8 i$ $= 8i$

Answer 2 · 2018-03-01T21:26:16

$\sqrt{- 64} = 8 i$ $sqrt(-64)=8i$

Explanation:

On the set of complex numbers, the identity $\sqrt{a b} = \sqrt{a} \sqrt{b}$ $sqrt(ab)=sqrtasqrtb$ holds for any $a,binCC$ .

So $sqrt(-64)=sqrt(-1)sqrt64=i8=8i$

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Simplify $\sqrt{- 64}$ $sqrt(-64)$ ? Thanks

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Simplify $\sqrt{- 64}$ $sqrt(-64)$ ? Thanks