Slope of a curve $y = x^{2} - 3$ $y=x^2-3$ at the point where $x = 1$ $x=1$ ?

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Answer 1 · 2014-09-21T15:14:32

First you need to find $f'(x)$ , which is the derivative of $f(x)$ .

$f'(x)=2x-0=2x$

Second, substitute in the value of x, in this case $x=1$ .

$f'(1)=2(1)=2$

The slope of the curve $y=x^2-3$ at the $x$ value of $1$ is $2$ .

Slope of a curve y=x^2-3y=x2−3y=x^2-3 at the point where x=1x=1x=1?