The density of gold is 19.5 g/cm. What is this value in kilograms per cubic meter?

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The density of gold is 19.5 g/cm. What is this value in kilograms per cubic meter?

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Answer 1 · 2017-03-06T07:17:05

$ρ = 19.5 \times 10^{3} \cdot k g \cdot m^{- 3}$ $rho=19.5xx10^3*kg*m^-3$

Explanation:

$ρ = 19.5 \cdot g \cdot c m^{3} = \frac{19.5 \cdot 10^{- 3} \cdot k g}{{(10^{- 2} m)}^{3}}$ $rho=19.5*g*cm^3=(19.5*10^-3*kg)/(10^-2m)^3$

$\frac{19.5 \times 10^{- 3} \cdot k g}{10^{- 6} m^{3}}$ $(19.5xx10^-3*kg)/(10^-6m^3)$

$(19.5 \times 10^{- 3} \cdot k g \times 10^{6}) m^{- 3}$ $(19.5xx10^-3*kgxx10^6)m^-3$ because $(\frac{1}{x^{- 1}} = \frac{1}{\frac{1}{x}} = x)$ $(1/x^-1=1/(1/x)=x)$

$= 19.5 \times 10^{3} \cdot k g \cdot m^{- 3}$ $=19.5xx10^3*kg*m^-3$

The price of gold is currently $$ 1232 - 10 \cdot U S D \cdot {troy ounce}^{- 1}$ $$1232-10*USD*"troy ounce"^-1$ .

Given that a $troy ounce$ $"troy ounce"$ $\equiv$ $-=$ $31.1 \cdot g$ $31.1*g$ , how much is your nugget worth?

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The density of gold is 19.5 g/cm. What is this value in kilograms per cubic meter?

1 Answer

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