The first two terms of a geometric sequence are a1 = 1⁄3 and a2 = 1⁄6. What is a8, the eighth term?

1 Answer
Aug 12, 2016

Use the formula t_n = a xx r^(n - 1)tn=a×rn1

Explanation:

Let's first find the value of rr, the common ratio.

r = t_2/t_1r=t2t1

r = (1/6)/(1/3)r=1613

r = 1/6 xx 3r=16×3

r = 1/2r=12

Now we can us the formula.

t_n = a xx r^(n - 1)tn=a×rn1

t_8 = 1/3 xx (1/2)^(8 - 1)t8=13×(12)81

t_8 = 1/8 xx 1/128t8=18×1128

t_8 = 1/1024t8=11024

Hopefully this helps!