Question

The latent heat of vaporization of water is 2260 J/g. How many grams of water at 100°C can be converted to steam by 226,000 J of energy?

Answer 1

The answer is: `m=100g`.

To answer to this question it is sufficient to use this equation:

`Q=Lm`

where

`Q` is the amount of heat needed to convert water in steam;

`L` is the latent heat of vaporization of water;

`m` is the mass of the water.

So:

`m=Q/L=(226000J)/(2260J/g)=100g`.