Question

The sum of three consecutive odd integers is 351, how do you find the three integers?

Answer 1

I got: `115,117 and 119`

Explanation:

let us call our integers:
`2n+1`
`2n+3`
`2n+5`
we get:
`2n+1+2n+3+2n+5=351`
rearrange:
`6n=351-9`
so that:
`n=342/6=57`
our integers will then be:
`2n+1=115`
`2n+3=117`
`2n+5=119`

Answer 2

115, 117 & 119

Explanation:

We can represent the three integers by using the variable `x`

1st odd integer `=x`
2nd odd integer `=x+2` consecutive integers would be `x+1`
3rd odd integer `=x+4`

The sum means we need to add

`x + x +2 + x + 4 = 351`

Combine like terms
`3x + 6 = 351`

Use additive inverse to isolate the variable term
`3x cancel(+6) cancel(-6)= 351-6`

`3x = 345`

Use the multiplicative inverse to isolate the variable
`(cancel3x)/cancel3 = 345/3`

`x =115`
`x+2=117`
`x + 4 = 119`