Question

The volume of a gas at 155 kPa changes from 22.0 L to 10.0 L. What is the new pressure if the temperature remains constant?

Answer 1

Approx. `320*kPa`

Explanation:

`Pprop1/V` or `PV=k` at constant `T`. This is Boyle's Law.

If we solve for `k`, `P_1V_1=P_2V_2`

Or, `P_2=(P_1V_1)/V_2` `=` `(155*kPaxx22.0*L)/(10*L)`