Two circles having equal radii $r_{1}$ $r_1$ and touching a line $l$ $l$ on the same side of $l$ $l$ are at a distance of $x$ $x$ from each other. Third circle of radius $r_{2}$ $r_2$ touches the two circles. How do we find the height of third circle from $l$ $l$ ?

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Answer 1 · 2017-07-06T11:46:06

See below.

Supposing that $x$ $x$ is the distance between perimeters and

supposing that $2 (r_{1} + r_{2}) > x + 2 r_{1}$ $2(r_1+r_2)gt x+2r_1$ we have

$h = \sqrt{{(r_{1} + r_{2})}_{1}^{2} - {(r_{1} + \frac{x}{2})}_{1}^{2}} + r_{1} - r_{2}$ $h = sqrt((r_1+r_2)^2-(r_1+x/2)^2)+r_1-r_2$

$h$ $h$ is the distance between $l$ $l$ and the perimeter of $C_{2}$ $C_2$

Two circles having equal radii r1r_1 and touching a line llon the same side of ll are at a distance of xx from each other. Third circle of radius r2r_2 touches the two circles. How do we find the height of third circle from ll?