Question

Two corners of an isosceles triangle are at `(2 ,6 )` and `(3 ,8 )`. If the triangle's area is `48`, what are the lengths of the triangle's sides?

Answer 1

Measure of the three sides are (2.2361, 49.1212, 49.1212)

Explanation:

Length `a = sqrt((3-2)^2 + (8-6)^2) = sqrt 5 = 2.2361`

Area of `Delta = 64`
`:. h = (Area) / (a/2) = 48 / (2.2361/2) = 64 / 1. 1181= 43.9327`
`side b = sqrt((a/2)^2 + h^2) = sqrt((1.1181)^2 + (43.9327)^2)`
`b = 49.1212`

Since the triangle is isosceles, third side is also `= b = 49.1212`

Measure of the three sides are (2.2361, 49.1212, 49.1212)