Question

Two corners of an isosceles triangle are at `(8 ,6 )` and `(7 ,5 )`. If the triangle's area is `64`, what are the lengths of the triangle's sides?

Answer 1

Measure of the three sides are (1.414, 90.5261, 90.5261)

Explanation:

Length `a = sqrt((8-7)^2 + (6-5)^2) = sqrt 2 = 1.414`

Area of `Delta = 64`
`:. h = (Area) / (a/2) = 64 / (1.414/2) = 64 / 0.707 = 90.5233`
`side b = sqrt((a/2)^2 + h^2) = sqrt((0.707)^2 + (90.5233)^2)`
`b = 90.5261`

Since the triangle is isosceles, third side is also `= b = 90.5261`

Measure of the three sides are (1.414, 90.5261, 90.5261)